Processing math: 100%

Amazon Ads

Thursday, November 7, 2019

Calculus - MAT 140 (UFV)

In this post, we shall be posting some problems solved,

1.  1xx31dx

Note that, I=x2x3x31dx

Set u=x31.

Hence du=3x2 dx.

As a result we have,

I=1/3duu(u+1)=2/3v dvv(v2+1) (Substituting u=v2we get du=2v dv)=(2/3)tan1(x31)





No comments:

Post a Comment

A trip to Buzios, Arraial do Cabo and Cabo Frio - Brazil

What a wonderful trip it was I must say. Of course, there were some downs as well, as expected. We started off with Buzios.  If you ever pla...